CBSE has announced the
standardization/normalization procedure for class 12 board exam marks in preparing all India JEE Main 2013 merit list. Here is what the CBSE Notice says
The JEE Interface Group (JIG) has decided that 50% of
Boards marks be standardized by equating percentile amongst different
boards/examining bodies and anchoring them to All India JEE-Main percentiles,
and 50% be normalized by equating each Board’s/examining Body’s percentile with
JEE(Main) percentile marks of respective Boards /examining bodies.
The detailed procedure for normalization of Board
marks will be as follows:
Note down the aggregate marks (A0) obtained by each
student in JEE- Main.
Compute the percentile (P) of each student on the basis
of aggregate marks in his/her own board (B0) computed from the list of five
subjects specified (each marked out of 100). The percentile is to be computed
among all students of the board whose subject combinations meet the eligibility
criteria of JEE-Main.
Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level.
Regard this as B1.
Also, determine the JEE- Main aggregate marks
corresponding to percentile (P) among the set of aggregate scores obtained in
the JEE- Main by the students of that board. Regard this as B2.
The normalized board score of the candidate will be
computed as:
B (final) =
0.5 * (B1 + B2)
For the purpose of admission to CFTIs where it has been
decided to use the JEE Mains performance and the Normalized Board
performance in the 60:40 ratio, the composite score for drawing the merit
list will be computed as:
C = 0.6 * AO
+ 0.4 * B (final),
Five subjects to be used for normalization:
- Physics
- Mathematics
- Any one of the subjects Chemistry, Biology,
Biotechnology and Computer Science
- One language
- Any subject other than the above four subjects.
In respect of 3, 4 and 5, the best mark in a given
category will be chosen.
For any query please write to
jeemainnormalisation2013@gmail.com .
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